Physics - Circular Motion Question with Solution | TestHub

PhysicsCircular MotionDynamicsHard2 minPYQ_2023

PhysicsHardsingle choice

A coin placed on a rotating table just slips when it is placed at a distance of $1 cm$ from the centre. If the angular velocity of the table is halved, it will just slip when placed at a distance of _____ from the centre:

Options:

Answer:

Solution:

The coin will slip when

$μ m g = m ω^{2} r$

$\Rightarrow μ g = ω^{2} \times 1 cm . . . (i)$

Now, $ω' = \frac{ω}{2}$

$μ g = {(\frac{ω}{2})}^{2} R . . . (i i)$

Hence we can write from (i) and (ii)

$ω^{2} \times 1 cm = \frac{ω^{2}}{4} R \Rightarrow R = 4 cm$

Stream:JEESubject:PhysicsTopic:Circular MotionSubtopic:Dynamics

⏱ 2mℹ️ Source: PYQ_2023

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