A ball of mass ( m ) 0 . 5 kg is attached to the end of a string having a length ( L ) 0 . 5 m . The ball is rotated on a horizontal circular path about the vertical axis. The maximum tension that the

Question

A ball of mass ( m ) 0 . 5 kg is attached to the end of a string having a length ( L ) 0 . 5 m . The ball is rotated on a horizontal circular path about the vertical axis. The maximum tension that the string can bear is 324 N . The maximum possible value of the angular velocity of ball (in rad s - 1 ) is

TestHub · Accepted Answer

r = l sin θ T cos θ component will cancel m g . T sin θ component will provide the necessary centripetal force to the ball towards centre C. Therefore T sin θ = m r ω 2 = m ( l sin θ ) ω 2 or T = m l ω 2 Therefore ω = T m l or ω max = T max m l = 324 0.5 = 36 rad s - 1

Physics - Circular Motion Question with Solution | TestHub

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