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Physics - Circular Motion Question with Solution | TestHub

PhysicsCircular MotionMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

A ball of mass $m = 0.5 kg$ is attached to the end of a string having length $L = 0.5 m$ . The ball is rotated on a horizontal circular path about the vertical axis. The maximum tension that the string can bear is $324 N$ . The maximum possible value of the angular velocity of ball (in $rad s^{- 1}$ ) is

Options:

Answer:

Solution:

$T sin θ = m ω^{2} r$

$T sin θ = m ω^{2} L sin θ$

$\Rightarrow T = m ω^{2} L$

$\Rightarrow 324 = \frac{1}{2} (ω^{2}) \frac{1}{2}$

Therefore $ω = 36 rad s^{- 1}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Circular MotionSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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