A particle is moving along a circular path with a constant speed of 10 ms − 1 . What is the magnitude of the change in velocity of the particle, when it moves through an angle of 6 0 ∘ around the cent

Question

A particle is moving along a circular path with a constant speed of 10 ms − 1 . What is the magnitude of the change in velocity of the particle, when it moves through an angle of 6 0 ∘ around the centre of the circle?

TestHub · Accepted Answer

Change in velocity, ∣Δ v ∣ = v 1 2 ​ + v 2 2 ​ + 2 v 1 ​ v 2 ​ cos ( π − θ ) ​ = 2 v sin 2 θ ​ ( ∵ ​ v 1 ​ ​ = ​ v 2 ​ ​ ) = v = ( 2 × 10 ) × sin ( 3 0 ∘ ) = 2 × 10 × 2 1 ​ = 10 m / s ​

Physics - Circular Motion Question with Solution | TestHub

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