A rod of length 5 L is bent right angle keeping one side length as 2 L.

The position of the centre of mass of the system: (Consider $L = 10 cm$ )

Question

A rod of length 5 L is bent right angle keeping one side length as 2 L. The position of the centre of mass of the system: (Consider L = 10 cm )

TestHub · Accepted Answer

x com ​ = 5 m 2 m ( 10 ) + 3 m ( 0 ) ​ = 4 cm y com ​ = 5 m 2 m ( 0 ) + 3 m ( 15 ) ​ = 9 cm r com ​ = 4 i ^ + 9 j ^ ​

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