Start Free Mock LoginAlready registered? Login here

Physics - Center of Mass Question with Solution | TestHub

PhysicsCenter of MassCollisionMedium2 minai-gemini

PhysicsMediumsingle choice

A ball of mass $m$ moving with velocity $v = v_{0} \hat{i} + v_{0} \hat{j}$ collides elastically with a smooth vertical wall perpendicular to the x-axis. If the collision occurs at $x = 0$ , what is the velocity of the ball immediately after the collision?

Options:

Answer:

Solution:

For an elastic collision with a smooth vertical wall perpendicular to the x-axis, the component of velocity perpendicular to the wall (x-component) reverses, while the component parallel to the wall (y-component) remains unchanged. Initial velocity components are $v_{x} = v_{0}$ and $v_{y} = v_{0}$ . After collision, $v_{x}^{'} = - v_{0}$ and $v_{y}^{'} = v_{0}$ . Therefore, the final velocity is $v^{'} = - v_{0} \hat{i} + v_{0} \hat{j}$ .

Stream:JEESubject:PhysicsTopic:Center of MassSubtopic:Collision

⏱ 2mℹ️ Source: ai-gemini

Doubts & Discussion

Loading discussions...