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Physics - Center of Mass Question with Solution | TestHub

PhysicsCenter of MassMomentum conservationMedium3 minQB

PhysicsMediumsingle choice

Block A is projected with speed v on a smooth horizontal surface towards block B as shown. Assume all the collisions to be elastic. Find the total no. of collision that will take place :- $(A = m, B = 2 m, C$ $= 9 m$ )

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Answer:

Solution:

A hits B: $v_{A} = - \frac{v}{3}, v_{B} = \frac{2 v}{3}$ . B hits C: $v_{B}^{'} = - \frac{14 v}{33}, v_{C} = \frac{8 v}{33}$ . B $(- \frac{14 v}{33})$ is faster than $A (- \frac{11 v}{33})$ and catches it: collision 3. After it: $v_{A} = - \frac{5 v}{11} \approx - 0.4545 v, v_{B} = - \frac{50 v}{99} \approx - 0.505 v$ : B still faster, collision 4. After it: $v_{A} = - \frac{155 v}{297} \approx - 0.522 v, v_{B} = - \frac{140 v}{297} \approx - 0.471 v$ : A pulls ahead, no more collisions. Answer: (C) 4

Stream:JEESubject:PhysicsTopic:Center of MassSubtopic:Momentum conservation

⏱ 3mℹ️ Source: QB

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