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Physics - Center of Mass Question with Solution | TestHub

PhysicsCenter of MassCollisionMedium2 minQB

PhysicsMediumsingle choice

A block of mass m moving with speed v collides with another block of mass 2m at rest. The lighter block comes to rest after the collision. The coefficient of restitution is :

Options:

Answer:

Solution:

Momentum is conserved during the collision.

$m v = (2 m) v_{2}$

$v_{2} = \frac{v}{2}$

The lighter block stops, so the speed of separation is the speed of the heavier block.

$e = \frac{v _{2} - 0}{v - 0} = \frac{1}{2}$

Option A.

Stream:JEESubject:PhysicsTopic:Center of MassSubtopic:Collision

⏱ 2mℹ️ Source: QB

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