Physics - Center of Mass Question with Solution | TestHub
A bullet of mass moving with velocity horizontally embeds itself into a block of mass initially at rest on a frictionless horizontal surface. The combined mass then slides on a rough horizontal surface with coefficient of kinetic friction (take ). Match the following quantities:
List - I | List - II |
|---|---|
(P) Speed of the combined mass immediately after the collision (in m/s) | (1) |
(Q) Kinetic energy lost during the collision (in J) | (2) |
(R) Magnitude of impulse exerted by the bullet on the block during the collision (in Ns) | (3) |
(S) Time taken for the combined mass to come to rest on the rough surface (in s) | (4) |
Options:
Answer:
Solution:
For P: By conservation of momentum, . So, . (P)-(1). For Q: Kinetic energy lost is . (Q)-(2). For R: Impulse on the block is . (R)-(3). For S: The deceleration on the rough surface is . Time to come to rest is . (S)-(1).
