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Physics - Center of Mass Question with Solution | TestHub

PhysicsCenter of MassCalculate of COMMedium2 minQB

PhysicsMediuminteger

In the given figure four rods $AB, BC, CD$ and DA have mass $m, 2 m, 3 m$ and 4 m respectively. In which of the regions (numbered 1, 2, 3, 4) the centre of mass of system lies?

Answer:

Solution:

Each rod's mass acts at its midpoint. With A(0,0), B(s,0), C(s,s), D(0,s): midpoints AB (0.5s, 0) mass m, BC (s, 0.5s) mass 2m, CD (0.5s, s) mass 3m, DA (0, 0.5s) mass 4m.

$X = \frac{0.5 s ( m ) + s ( 2 m ) + 0.5 s ( 3 m )}{10 m} = 0.4 s, Y = \frac{0.5 s ( 2 m ) + s ( 3 m ) + 0.5 s ( 4 m )}{10 m} = 0.6 s$ .

Point (0.4s, 0.6s): left of centre, above centre - region 2. Answer: 2.

Stream:JEESubject:PhysicsTopic:Center of MassSubtopic:Calculate of COM

⏱ 2mℹ️ Source: QB

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