A body of mass 2 g, moving along the positive x-axis in gravity free space with velocity 20 cm/s explodes at x = 1 m, t = 0 into two pieces of masses 2 / 3 g and 4 / 3 g . After 5 s, the lighter piece

Question

A body of mass 2 g, moving along the positive x-axis in gravity free space with velocity 20 cm/s explodes at x = 1 m, t = 0 into two pieces of masses 2 / 3 g and 4 / 3 g . After 5 s, the lighter piece is at the point : ( 3 m, 2 m, − 4 m ) . Then the position of the heavier piece at this moment, in metres is :-

TestHub · Accepted Answer

No external force, so the centre of mass moves uniformly: at t = 5 s it is at $(1 + 0.2 \times 5, 0, 0) = (2, 0, 0)$ .

$\frac{2}{3} (3, 2, - 4) + \frac{4}{3} r_{2} = 2 (2, 0, 0)$ gives $r_{2} = (1.5, - 1, + 2) m$ , which matches none of (A)-(C).

Answer: (D) None

Physics - Center of Mass Question with Solution | TestHub

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