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Physics - Center of Mass Question with Solution | TestHub

PhysicsCenter of MassVariable massMedium2 minQB

PhysicsMediuminteger

Figure shows cone of mass 200 gm, suspended by a vertical jet of water from a garden hose. The flow rate is 0.2 kg/sec. The water rises 8m if unimpeded. Find the height of the cone top surface (h in m) at which water strike. Assume the water emerges horizontally from holes at the top of cone.

Answer:

Solution:

Jet speed at the cone top: from $\frac{1}{2} u^{2} = g \times 8$ , $u^{2} = 16 g$ ; after rising $h$ : $v = 16 g - 2 g h$ . Momentum flux supports the cone's weight: $v \frac{d m}{d t} = m g$ ⇒ $16 g - 2 g h \times 0.2 = 0.2 g$ . $16 - 2 h = g = 10$ ⇒ $h = 3$ m

Stream:JEESubject:PhysicsTopic:Center of MassSubtopic:Variable mass

⏱ 2mℹ️ Source: QB

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