Physics - Center of Mass Question with Solution | TestHub
As shown in figure there is a small bob having mass 1 kg is attached to the string having negligible mass. Bob is released as shown in figure. Initially when spring is in natural length. (g = 10 m/s)
Just after achieving maximum compression in the spring as per previous problem, a bullet of mass 100g strikes to the block in such a manner that there is maximum loss in mechanical energy due to collision. The velocity of bullet is. Find the value of v so that elongation of spring is equal to compression of spring? (Assuming there is no further collision with bob)
Options:
Answer:
Solution:
Maximum energy loss means the bullet (0.1 kg) embeds: combined 3.1 kg moves at. Spring PE is the same at 0.96 m compression and 0.96 m elongation, so the bullet-collision KE is spent only against friction over... Answer: (B)
