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PhysicsCenter of MassImpulse momentum theoremEasy2 minPYQ_2023
PhysicsEasysingle choice

A bullet of 10 g leaves the barrel of gun with a velocity of 600 m s-1. If the barrel of gun is 50 cm long and mass of gun is 3 kg, then value of impulse supplied to the gun will be:

Options:

Answer:
A
Solution:

The formula to calculate the impulse J on the gun is given by

J=mv-u   ...1

where, m is the mass, u is the initial velocity and v is the final velocity of the bullet.

Substitute the values of the known parameters into equation (1) to calculate the required impulse.

J=10 g×1 kg1000 g×600-0 m s-1= 6 N s

Stream:JEESubject:PhysicsTopic:Center of MassSubtopic:Impulse momentum theorem
2mℹ️ Source: PYQ_2023

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