A particle of mass m moving with velocity v collides with a stationary particle of mass 2 m . After collision, they stick together and continue to move together with velocity

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TestHub · Accepted Answer

The law of conservation of momentum is given as
$m_{1} u + m_{2} u' = (m_{1} + m_{2}) v'$
The given data is
$u = v u' = 0 m s^{- 1} m_{1} = m m_{2} = 2 m$
Using the conservation of momentum equation,
$m v + 2 m (0) = (m + 2 m) v' \Rightarrow v' = \frac{m v}{3 m} = \frac{v}{3}$

Physics - Center of Mass Question with Solution | TestHub

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