TestHub
TestHub

Physics - Center of Mass Question with Solution | TestHub

PhysicsCenter of MassMomentum conservationMedium2 minPYQ_2022
PhysicsMediumsingle choice

A ball of mass0.15 kghits the wall with its initial speed of12 m s-1and bounces back without changing its initial speed. If the force applied by the wall on the ball during the contact is100 N. calculate the time duration of the contact of ball with the wall.

Options:

Answer:
B
Solution:

Given: m=1.5 kg & u=12 m s-1

Change in the momentum of the ball after the collision=2mv

=2×1.5×12

=36 N s

As the force applied during collision is equal to 100 N and if t is the duration of collision, so

100×t=Δp

t=36100 s

t=36×10-2 s=0.036 s

Stream:JEESubject:PhysicsTopic:Center of MassSubtopic:Momentum conservation
2mℹ️ Source: PYQ_2022

Doubts & Discussion

Loading discussions...