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PhysicsCenter of MassMomentum conservationEasy2 minPYQ_2020
PhysicsEasyinteger

A bodyAof massm=0.1 kghas an initial velocity of3i^ m s-1. It collides elastically with another bodyBof the same mass which has an initial velocity of5j^ m s-1. After the collision,Amoves with a velocityv=4i^+j^ m s-1. The energy ofBafter the collision is written asx10 J. The value ofxis

Answer:
1
Solution:

Using the principle of conservation of linear momentum

0.1×3i^ + 0.1×5j^ = 0.1×4i^+j^ + 0.1×v

v=-i^ + j^ m s-1

v=v=2 m s-1

KB=12×0.1×v2=110 J

x=1

Stream:JEESubject:PhysicsTopic:Center of MassSubtopic:Momentum conservation
2mℹ️ Source: PYQ_2020

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