Two particles of equal mass m have respective initial velocities u i ^ and u i ^ + j ^ 2 . They collide completely inelastically. The energy lost in the process is:

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Conserving momentum m u i ^ + m u 2 i ^ + u 2 j ^ = 2 m u 1 i ^ + u 2 j ^ On solving u 1 = 3 u 4 and u 2 = u 4 Change in K.E. 1 2 m u 2 + 1 2 m u 2 2 2 - 1 2 2 m 9 u 2 16 + u 2 16 = 3 m u 2 4 - 5 m u 2 8 = m u 2 8

Physics - Center of Mass Question with Solution | TestHub

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