Physics - Center of Mass Question with Solution | TestHub

Change in momentum for each bullet fired is $$=\frac{40}{1000}\times 1200=48\mathrm{N}$$ If a bullet fired exerts a force of $48\mathrm{N}$ on man's hand so $\rho$ man can exert maximum force of $144\mathrm{N}$, number of bullets that can be fired $=144/48=3$ bullets.