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Physics - Capacitor Question with Solution | TestHub

PhysicsCapacitorBasic capacitor analysis with dielectricEasy2 minQB

PhysicsEasysingle choice

Capacitance of a capacitor made by a thin metal foil is 2 μF.If the foil is folded with paper of thickness 0.15 mm, dielectric constant of paper is 2.5 and width of paper is 400 mm,the length of foil will be

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Answer:

Solution:

If length of the foil is $l$ then

$C = \frac{K ε_{0} \cdot l \times b}{d}$

$\Rightarrow 2 \times 1 0^{- 6} = \frac{2 \cdot 5 \times 8 \cdot 85 \times 1 0^{- 12} \times l \times 400 \times 1 0^{- 3}}{0 \cdot 15 \times 1 0^{- 3}}$

$\Rightarrow l = 33 \cdot 9 m$

Stream:JEESubject:PhysicsTopic:CapacitorSubtopic:Basic capacitor analysis with dielectric

⏱ 2mℹ️ Source: QB

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