Physics - Capacitor Question with Solution | TestHub

In $L-C$ oscillations, total time in one complete cycle is, $T=2\pi \sqrt{LC}$ $\begin{array}{rl}& T=2\pi \sqrt{25\times 10^{-3}\times 10\times 10^{-6}}\\ & \Rightarrow T=2\pi \sqrt{25\times 10^{-8}}\\ & =\pi \times 10^{-3}\sec \end{array}$ After time $T/4$ capacitor is fully discharged and current in circuit will be maximum, then $\frac{T}{4}=\frac{\pi \times 10^{-3}}{4}=\frac{\pi }{4}\mathrm{ms}$