Physics - Capacitor Question with Solution | TestHub

To find the equivalent capacitance, first, the two capacitors in series are combined: $C_{series}=\frac{C\times C}{C+C}=\frac{C^2}{2C}=\frac{C}{2}$. This combination is then in parallel with the third capacitor: $C_{eq}=C_{series}+C=\frac{C}{2}+C=\frac{3C}{2}$. Given $C=1.2\mu F$, $C_{eq}=\frac{3\times 1.2\mu F}{2}=1.8\mu F$.