Physics - Capacitor Question with Solution | TestHub

the charge flown through wires as a function of time t is $\frac{{\mathrm{q}}_0\mathrm{C}}{{\mathrm{C}}_1}\times \left[1-{\mathrm{e}}^{-\mathrm{t}/\mathrm{RC}}\right]$ where, $\mathrm{C}=\frac{{\mathrm{C}}_1{\mathrm{C}}_2}{{\mathrm{C}}_1+{\mathrm{C}}_2}$

The total heat dissipated in the circuit during the discharging process of ${\mathrm{C}}_1$ is $\frac{{\mathrm{q}}_0^2}{2{\mathrm{C}}_1^2}\times \mathrm{C}$ at a time when power consumed by Resistor and capacitor ${\mathrm{C}}_2$ is same the potential difference across

${\mathrm{C}}_1$ is twice of that across ${\mathrm{C}}_2$

Immediately after closing the switch the current in the circuit is zero