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Physics - Capacitor Question with Solution | TestHub

PhysicsCapacitorCircuit AnalysisMedium2 minPYQ_2020

PhysicsMediumsingle choice

In the circuit shown, charge on the $5 μ F$ capacitor is :

Options:

Answer:

Solution:

$V_{B} = 6 V_{C} = x V_{D} = 6$

$- 91 + 92 + 93 = 0$
$- 2 (6 - x) + 4 (x - 6) + 5 (x - 0) = 0$
$- 12 + 2 x + 4 x - 24 + 5 x = 0$
$11 x = 36 \Rightarrow x = \frac{36}{11}; q_{3} = 5 \times \frac{36}{11} = \frac{180}{11} μ C$

Stream:JEESubject:PhysicsTopic:CapacitorSubtopic:Circuit Analysis

⏱ 2mℹ️ Source: PYQ_2020

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