Physics - Capacitor Question with Solution | TestHub

Between A and B, there are three parallel branches.

Top branch:

$$C_{top}=\frac{23\times 7}{23+7}=\frac{161}{30}\mu F$$

Middle branch:

$$C_{CB}=\frac{13\times 1}{13+1}=\frac{13}{14}\mu F$$

$$C_{middle}=\frac{12\times \frac{13}{14}}{12+\frac{13}{14}}=\frac{156}{181}\mu F$$

Bottom branch:

$$C_{bottom}=\frac{10\times 1}{10+1}=\frac{10}{11}\mu F$$

Equivalent capacitance:

$$C_{eq}=\frac{161}{30}+\frac{156}{181}+\frac{10}{11}\approx 7.5\mu F=\frac{15}{2}\mu F$$

$$\boxed{C_{eq}=\frac{15}{2}\mu F}$$

Correct option: (B)