Physics - Capacitor Question with Solution | TestHub

PhysicsCapacitorCircuit AnalysisMedium2 minQB

PhysicsMediummultiple choice

In the given figure if A is connected with C and B is connected with D, then :-

Answer:

A, B

Solution:

Common potential

$V_{C} = \frac{C _{1} V _{1} + C _{2} V _{2}}{C _{1} + C _{2}} = 14$ V

$q_{A} = C_{1} V_{C} = 28 μ C$

$Δ q = C_{1} V_{1} - C_{1} V_{C} = 12 μ C$

Heat produced

$H = \frac{1}{2} \frac{C _{1} C _{2}}{C _{1} + C _{2}} (V_{1} - V_{2})^{2} = 60 μ J$

Stream:JEESubject:PhysicsTopic:CapacitorSubtopic:Circuit Analysis

⏱ 2mℹ️ Source: QB

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