Physics - Capacitor Question with Solution | TestHub

In steady state the capacitors are open, so each resistor row carries $I=\frac{120}{6}=20$ A.

Upper row potentials: $100$ V after the $1\Omega$ and $60$ V after the $2\Omega$; lower row: $80$ V after the $2\Omega$ and $60$ V after the $1\Omega$.

$C_1$ sits across $100-80=20$ V, so $Q_1=2\times 20=40\mu C$ - (D) correct; $C_2$ sits across $60-60=0$ V, so its charge is zero - (B) correct.