The circuit involves two ideal cells connected to a 1 mF capacitor via a key K . Initially the key K is in position 1 and the capacitor is charged fully by 2 V cell. The key is pushed to position 2 .

Question

The circuit involves two ideal cells connected to a 1 mF capacitor via a key K . Initially the key K is in position 1 and the capacitor is charged fully by 2 V cell. The key is pushed to position 2 . Column-I gives physical quantities involving the circuit after the key is pushed from position 1. Column-II gives corresponding results. Match the statements in Column-I with the corresponding values in Column-II and indicate your answer by darkening appropriate bubbles in the $4 \times 4$ matrix given in the OMR.

TestHub · Accepted Answer

The initial charge on capacitor = CV i ​ = 1 × 2 μ C = 2 μ C The final charge on capacitor = CV f ​ = 1 × 4 μ C = 4 μ C ∴ Net charge crossing the cell of emf 4 V is q f ​ − q i ​ = 4 − 2 = 2 μ C The magnitude of work done by cell of emf 4 V is W = ( q f ​ − q i ​ ) 4 = 8 μ J The gain in potential energy of capacitor is Δ U = 2 1 ​ C ( V f 2 ​ − V i 2 ​ ) = 2 1 ​ × [ 4 2 − 2 2 ] μ J = 6 μ J Net heat produced in circuit is Δ H = W − Δ U = 8 − 6 = 2 μ J

Physics - Capacitor Question with Solution | TestHub

Options:

Doubts & Discussion