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Physics - Capacitor Question with Solution | TestHub

PhysicsCapacitorForce & Energy analysisMedium2 minQB

PhysicsMediumsingle choice

Two identical capacitors have same capacitance $C$ . One of them is charged to the potential $V$ and other to the potential $2 V$ . The negative ends of both are connected together. When the positive ends are also joined together, the decrease in energy of the combined system is :

Options:

Answer:

Solution:

The common potential after connection would be, $V_{C} = \frac{q_{n e t}}{C_{n e t}} = \frac{C V + C (2 V)}{2 C}$

$\Rightarrow V_{C} = \frac{3 V}{2}$

Therefore, loss of energy

$= \frac{1}{2} C V^{2} + \frac{1}{2} C {(2 V)}^{2} - \frac{1}{2} 2 C {(\frac{3 V}{2})}^{2}$

$= (\frac{C V^{2}}{4})$

Stream:JEESubject:PhysicsTopic:CapacitorSubtopic:Force & Energy analysis

⏱ 2mℹ️ Source: QB

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