The work done in placing a charge of 8 × 1 0 − 18 coulomb on a condenser of capacity 100 micro-farad is

Work done = 2 1 c q 2 = 2 × 100 × 1 0 − 8 ( 8 × 1 0 − 18 ) 2 = 32 × 1 0 − 32 J

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PhysicsCapacitorForce & Energy analysisEasy2 minQB

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The work done in placing a charge of $8 \times 1 0^{- 18}$ coulomb on a condenser of capacity 100 micro-farad is

Answer:

Solution:

Work done $= \frac{1}{2} \frac{q ^{2}}{c} = \frac{( 8 \times 1 0 ^{- 18} ) ^{2}}{2 \times 100 \times 1 0 ^{- 8}} = 32 \times 1 0^{- 32} J$

Stream:JEESubject:PhysicsTopic:CapacitorSubtopic:Force & Energy analysis

⏱ 2mℹ️ Source: QB

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