Physics - Capacitor Question with Solution | TestHub

In parallel combination, the potential difference across each individual capacitor is the same as the potenital difference across the combination. So, potential difference across capacitor of capacity $\mathrm{C}$ is $\frac{V}{2}$. Charge on capacitor, $\mathrm{C}=\frac{Q}{V}$ $\therefore$ Charge on capacitor of capacity $\mathrm{C}=\frac{CV}{2}$