Physics - Capacitor Question with Solution | TestHub

PhysicsCapacitorForce & Energy analysisEasy2 minQB

PhysicsEasyinteger

If in steady state the energy stored in the capacitor (as shown in figure) is $N \times 1 0^{- 8} J$ , then find the value of N .

Answer:

Solution:

In steady state the capacitor branch carries no current, and the p.d. across the capacitor is $Δ V = 0.2$ V.

$U = \frac{1}{2} C (Δ V)^{2} = \frac{1}{2} \times 3 \times 1 0^{- 6} \times (0.2)^{2} = 6 \times 1 0^{- 8}$ J, so N = 6.

Stream:JEESubject:PhysicsTopic:CapacitorSubtopic:Force & Energy analysis

⏱ 2mℹ️ Source: QB

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