Physics - Capacitor Question with Solution | TestHub

Initial charge on the first capacitor is $Q=C_1{V}_1$

Initial charge on the second capacitor is zero.

When connected in parallel, the total charge remains conserved and the equivalent capacitance is $C_{eq}=C_1+C_2$

The resultant potential $V_2$ is given by $V_2=\frac{\text{Total Charge}}{\text{Total Capacitance}}$

$V_2=\frac{C_1{V}_1}{C_1+C_2}$