Physics - Capacitor Question with Solution | TestHub

Given half life $\mathrm{T}=3.8$ days; $\mathrm{t}=19$ days $\frac{\mathrm{N}}{{\mathrm{N}}_0}=?$ now $\frac{\mathrm{t}}{\mathrm{T}}=\frac{19}{3.8}=5$ $\Rightarrow \frac{\mathrm{N}}{{\mathrm{N}}_0}={\left(\frac{1}{2}\right)}^{\frac{\mathrm{t}}{\mathrm{T}}}={\left(\frac{1}{2}\right)}^5=\frac{1}{32}$ $\Rightarrow \mathrm{N}=\frac{{\mathrm{N}}_0}{32}=0.03{\mathrm{N}}_0$