Physics - Capacitor Question with Solution | TestHub

In a series combination of capacitors, the charge $Q$ on each capacitor is the same.

The potential difference across a capacitor is given by $V=\frac{Q}{C}$.

For the three capacitors, the potential differences are $V_1=\frac{Q}{C_1}$, $V_2=\frac{Q}{C_2}$, and $V_3=\frac{Q}{C_3}$.

The ratio of the potentials across the three capacitors is $V_1:V_2:V_3=\frac{Q}{C_1}:\frac{Q}{C_2}:\frac{Q}{C_3}$.

Since $Q$ is constant, the ratio becomes $\frac{1}{C_1}:\frac{1}{C_2}:\frac{1}{C_3}$.

Answer: $\frac{1}{{\mathrm{C}}_1}:\frac{1}{{\mathrm{C}}_2}:\frac{1}{{\mathrm{C}}_3}$