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Physics - Capacitor Question with Solution | TestHub

PhysicsCapacitorForce & Energy analysisEasy2 minPYQ_2024

PhysicsEasysingle choice

A 12 pF capacitor is connected to a 50 V battery, the electrostatic energy stored in the capacitor in nJ isNEET 2024 (Re-NEET)

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Solution:

Electrostatic energy stored $U = \frac{1}{2} C V^{2}$ $= \frac{1}{2} \times 12 \times 1 0^{- 12} \times (50)^{2}$ $= 6 \times 25 \times 1 0^{- 10}$ $= 15 \times 1 0^{- 9} J$ $= 15 nJ$

Stream:NEETSubject:PhysicsTopic:CapacitorSubtopic:Force & Energy analysis

⏱ 2mℹ️ Source: PYQ_2024

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