Physics - Capacitor Question with Solution | TestHub

$$\begin{array}{rl}\frac{1}{C_5}& =\frac{1}{C}+\frac{1}{C}+\frac{1}{C}\\ \therefore C_5& =\frac{C}{3}\end{array}$$ Now, ${\mathrm{C}}_5$ and $\mathrm{C}$ are connected in parallel, $$\therefore {\mathrm{C}}_{\text{net }}={\mathrm{C}}_{\mathrm{s}}+\mathrm{C}=\frac{\mathrm{C}}{3}+\mathrm{C}=\frac{4\mathrm{C}}{3}$$