Physics - Capacitor Question with Solution | TestHub

Change in energy $\Delta U=\frac{1}{2}\left[\frac{q_1^2-q_2^2}{C}\right]$ $$\begin{array}{l}=\frac{1}{2}\left[\frac{(0.5{)}^2-(0.1{)}^2}{48\times 10^{-6}}\right]\\ =\frac{1}{2}\left[\frac{0.25-0.01}{48\times 10^{-6}}\right]\\ =\frac{1}{2}\left[\frac{0.24}{48\times 10^{-6}}\right]\\ =\frac{1}{2}\left[\frac{10^4}{2}\right]\\ =2500\mathrm{J}\end{array}$$