Physics - Capacitor Question with Solution | TestHub
Two parallel plate capacitors and each having capacitance of are individually charged by a D.C. source. Capacitor is kept connected to the source and a dielectric slab is inserted between it plates. Capacitor is disconnected from the source and then a dielectric slab is inserted in it. Afterwards the capacitor is also disconnected from the source and the two capacitors are finally connected in parallel combination. The common potential of the combination will be _____ .
(Assuming Dielectric constant )
Answer:
Solution:
As source is connected in the process therefore, additional charge will be provided. Therefore, charge on .
Since source is disconnected, so its charge will remain the same. Then, charge on .
New capacitance in both cases will become, .
When they are connected in parallel charge will be equally divided so charge on one capacitor is .
So common potential,
.