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PhysicsCapacitorBasic capacitor analysis with dielectricEasy2 minPYQ_2022
PhysicsEasysingle choice

A parallel plate capacitor is formed by two plates each of area 30πcm2 separated by 1 mm. A material of dielectric strength 3.6×107 V m-1 is filled between the plates. If the maximum charge that can be stored on the capacitor without causing any dielectric breakdown is 7×10-6 C, the value of dielectric constant of the material is :

[Use 14πεo=9×109 N m2 C-2]

Options:

Answer:
D
Solution:

The dielectric strength given is 3.6×107 V m-1.and the separation is 1 mm. Therefore, maximum potential difference that can be applied will be,

Vmax=3.6×107×d.

Now,

C=qmaxVmaxkε0Ad=7×10-73.6×107×dk=dε0×30π×10-4×7×10-73.6×107×d=2.33

Stream:JEESubject:PhysicsTopic:CapacitorSubtopic:Basic capacitor analysis with dielectric
2mℹ️ Source: PYQ_2022

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