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Physics - Capacitor Question with Solution | TestHub

PhysicsCapacitorForce & Energy analysisEasy2 minPYQ_2022

PhysicsEasysingle choice

The force between the plates of a parallel plate capacitor of capacitance $C$ and distance of separation of the plates $d$ with a potential difference $V$ between the plate is

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Solution:

Total electric field between the plates of the capacitor. $E = \frac{V}{d}$ Then, electric field due to only one plate. $E_{1} = \frac{V}{2 d}$ $∴$ force of one plate on another. $F = E_{1} \times Q = E_{1} \times C V = \frac{V}{2 d} \times C V = \frac{C V ^{2}}{2 d}$

Stream:MHT_CETSubject:PhysicsTopic:CapacitorSubtopic:Force & Energy analysis

⏱ 2mℹ️ Source: PYQ_2022

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