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PhysicsCapacitorCircuit AnalysisEasy2 minPYQ_2021
PhysicsEasynumerical

A 2μF capacitor C1 is first charged to a potential difference of 10 V using a battery. Then the battery is removed and the capacitor is connected to an uncharged capacitor C2 of 8μF. The charge in C2 on equilibrium condition is μC. (Round off to the Nearest Integer)

Question diagram: A 2 μ F capacitor C 1 is first charged to a potential differ
Answer:
16.00
Solution:

20=C1+C2 VV=2 volt .

Q2=C2V=16 μC

=16

Stream:JEESubject:PhysicsTopic:CapacitorSubtopic:Circuit Analysis
2mℹ️ Source: PYQ_2021

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