For the given input voltage waveform V in ( t ) , the output voltage waveform V 0 ( t ) , across the capacitor is correctly depicted by :

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TestHub · Accepted Answer

When first pulse is applied the potential across capacitor is given by $V = V_{0} (1 - e^{- \frac{t}{R C}})$

When no pulse is applied, capacitor will discharge like $V = V_{0}^{'} e^{t / R C}$ when again, second pulse is applied $V = V_{0} (1 - e^{- \frac{t}{R C}})$

Using all three equations the correct graph is :

Physics - Capacitor Question with Solution | TestHub

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