Physics - Capacitor Question with Solution | TestHub

Equivalent capacitance of two parallel capacitors $10\mu \mathrm{F}$ and $6\mu \mathrm{F}=(10+6)\mu \mathrm{F}=16\mu \mathrm{F}$ This $16\mu \mathrm{F}$ capacitor is in series combination with $4\mu \mathrm{F}$ capacitor, $\therefore$ Equivalent capacitance of the entire combination $=\frac{16\times 4}{16+4}=\frac{64}{20}=3.2\mu \mathrm{F}$