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Physics - Capacitor Question with Solution | TestHub

PhysicsCapacitorBasic capacitor analysis with dielectricEasy2 minPYQ_2018

PhysicsEasysingle choice

Electric field inside the given capacitor with dielectric is $E$ and dielectric constant of material is $K$ . Find charge density $σ$ on the plates. (Given $E = 6 \times 1 0^{5} V / m, K = 6$ )

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Answer:

Solution:

$: E = \frac{σ}{ε _{0} \cdot K}; 6 \times 1 0^{5} = \frac{σ}{8.85 \times 1 0 ^{- 12} \times 6} σ = 36 \times 8.85 \times 1 0^{- 12} \times 1 0^{5} C / m^{2} σ = 3.18 \times 1 0^{- 5} C / m^{2}$

Stream:AIIMSSubject:PhysicsTopic:CapacitorSubtopic:Basic capacitor analysis with dielectric

⏱ 2mℹ️ Source: PYQ_2018

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