In the given circuit diagram, E = 5 V , r = 1 Ω , R 2 = 4 Ω , R 1 = R 3 = 1 Ω and C = 3 μ F Then, what will be the numerical value of charge on each plates of the capacitor.

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TestHub · Accepted Answer

Current will flow only through the branch containing resistance $R_{2}$

$∴ i = \frac{E}{R_{2} + r} = \frac{5}{4 + 1} = 1 A$

Potential difference across $R_{2}$

$= 1 \times 4 = 4 V$

If $q$ be the charge on each plate of capacitor, then

$\frac{q}{c} + \frac{q}{c} = 4$

or $\frac{2 q}{c} = 4$

or $\frac{2 q}{3 \times 10^{- 6}} = 4$

$q = 6 μC$

Physics - Capacitor Question with Solution | TestHub

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