A 5 μ F capacitor is charged by being connected to a 3 V battery. The battery is then disconnected. If the resistance of the dielectric material between the capacitor plates is 1 0 9 Ω , what is the c

Question

A 5 μ F capacitor is charged by being connected to a 3 V battery. The battery is then disconnected. If the resistance of the dielectric material between the capacitor plates is 1 0 9 Ω , what is the charge remaining on the capacitor 1 h after it has been disconnected ?

TestHub · Accepted Answer

​ T = RC ​ = ( 1 0 9 Ω ) ( 5 × 1 0 − 6 F ) = 5 × 1 0 3 s ​ = ( 60 s / min ) ( 60 min / h ) 5 × 1 0 3 s ​ = 3600 s / h 5000 s ​ = 1.4 h ​ The initial charge on the capacitor is ​ Q 0 ​ = C V = ( 5 × 1 0 − 6 F ) ( 3 V ) = 1.5 × 1 0 − 5 C After t = 1 h , t / T = ( 1 h ) / ( 1.4 h ) = 0.71 and Q ​ = Q 0 ​ e − t / T = ( 1.5 × 1 0 − 5 C ) ( e − 0.71 ) = ( 1.5 × 1 0 − 5 C ) ( 0.49 ) = 7.4 × 1 0 − 6 C ​ ​

Physics - Capacitor Question with Solution | TestHub

Options:

Doubts & Discussion