Two metal plates form a parallel plate condenser. The distance between the plates is d. A metal plate of thickness d /2 and of the same area is inserted completely between the plates. The ratio of cap

Question

Two metal plates form a parallel plate condenser. The distance between the plates is d. A metal plate of thickness d /2 and of the same area is inserted completely between the plates. The ratio of capacitances in the two cases (later to initial) is -

TestHub · Accepted Answer

Initial capacitance C 0 ​ = d ϵ 0 ​ A ​ . With a metal plate of thickness d /2 inserted, the effective distance between plates becomes d − d /2 = d /2 . New capacitance C f ​ = d /2 ϵ 0 ​ A ​ = d 2 ϵ 0 ​ A ​ = 2 C 0 ​ . The ratio C f ​ : C 0 ​ = 2 C 0 ​ : C 0 ​ = 2 : 1 .

Physics - Capacitor Question with Solution | TestHub

Options:

Doubts & Discussion

JEE Main (2026)