In the hydrogen atom, the electron is making 6.6 × 1 0 15 rps . If the radius of orbit is 0.53 × 1 0 − 10 m , then magnetic field produced at the centre of the orbit is

Current, i = q v B = 2 r μ 0 i = 2 r μ 0 q v = 2 × 0.53 × 1 0 − 10 4 π × 1 0 − 7 × 1.6 × 1 0 − 19 × 6.6 × 1 0 15 = 5.3 2 π × 1.6 × 6.6 = 12.513 T

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PhysicsCapacitorForce & Energy analysisHard2 minPYQ_2010

PhysicsHardsingle choice

In the hydrogen atom, the electron is making $6.6 \times 1 0^{15} rps$ . If the radius of orbit is $0.53 \times 1 0^{- 10} m$ , then magnetic field produced at the centre of the orbit is

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Solution:

Current, $i = q v$ $B = \frac{μ _{0}^{i}}{2 r} = \frac{μ _{0} q v}{2 r} = \frac{4 π \times 1 0 ^{- 7} \times 1.6 \times 1 0 ^{- 19} \times 6.6 \times 1 0 ^{15}}{2 \times 0.53 \times 1 0 ^{- 10}} = \frac{2 π \times 1.6 \times 6.6}{5.3} = 12.513 T$

Stream:VITEEESubject:PhysicsTopic:CapacitorSubtopic:Force & Energy analysis

⏱ 2mℹ️ Source: PYQ_2010

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