Physics - Capacitor Question with Solution | TestHub

A capacitor ${\mathrm{C}}_1(=\mathrm{C})$ is charged to a potential difference e is connected to a charging circuit by changing the switch S as shown. Assume the instant of switching as $\mathrm{t}=0$. Capacitor ${\mathrm{C}}_2$ is, initially uncharged, then, the charge on ${\mathrm{C}}_2(=\mathrm{C})$ is changing according to equation $;{\mathrm{q}}_2={\mathrm{Q}}_2\left(1-{\mathrm{e}}^{-\mathrm{t}/\delta }\right)$. where, $\delta$ is called time constant and ${\mathrm{Q}}_2$ is the steady state charge on ${\mathrm{C}}_2$. Let, ${\mathrm{Q}}_2={\mathrm{n}}_2(\mathrm{C}\epsilon )$ and $=\delta ={\mathrm{n}}_1(\mathrm{RC})$. Find $\left(\frac{{\mathrm{n}}_2}{{\mathrm{n}}_1}\right)$.